Linux list all users with groups

How can I find out which users are in a group within Linux?

I’ve recently been creating new users and assigning them to certain groups. I was wondering if there is a command that shows all the users assigned to a certain group? I have tried using the ‘groups’ command however whenever I use this it says ‘groups: not found’

That is the groups command. It is unlikely that you do not have it on Linux, since it is part of coreutils.

11 Answers 11

I prefer to use the getent command .

Since getent uses the same name service as the system, getent will show all information, including that gained from network information sources such as LDAP.

So for a group, you should use the following .

getent group name_of_group 

where name_of_group is replaced with the group you want to look up. Note that this only returns supplementary group memberships, it doesn’t include the users who have this group as their primary group.

There are a whole lot of other lookups that you can do . passwd being another useful one, which you’ll need to list primary groups.

The other answers doesn’t apply if you are not administrator and the group info is stored in other server.

This could be really confusing probably because of primary/secondary difference. I think this should be avoided in favor of sudo lid -g .I have a system where this answer lists 8 users in a group whereas sudo lid -g lists 10.

grep '^group_name_here:' /etc/group 

This only lists supplementary group memberships, not the user who have this group as their primary group. And it only finds local groups, not groups from a network service such as LDAP.

This could be really confusing probably because of primary/secondary difference. I think this should be avoided in favor of sudo lid -g .I have a system where this answer lists 8 users in a group whereas sudo lid -g lists 10.

This should NOT be the accepted answer. Modern Linux installations have multiple sources for user/group information — not just local /etc/passwd and /etc/group — e.g. nsswitch or sssd . Use getent passwd for user info & getent group for group information — this will cover all modern Linux configurations.

Easier to do groups [username]

If you want to list all local users and their local groups you can do

cat /etc/passwd | awk -F’:’ ‘< print $1>‘ | xargs -n1 groups

If you get «groups: command not found», it is likely you’ve edited your environmental path for the worse, to reset your path do PATH=$(getconf PATH)

It works for a particular group if | grep is added and gives the correct answer unlike getent group name_of_group or grep ‘^group_name_here:’ /etc/group

Instead of cat /etc/passwd , you should use gentent passwd so users in nis/ldap would still be listed. The only drawback is that it can take quite a while.

groupmems -g groupname -l

lists all users in the named group.

Note that groupmems is part of the shadow utils used on most Linux distros, however groupmems is currently absent from Debian and derivative (a bug now fixed but not included in any release yet (as of Nov 2016))

Also note that groupmems only deals with groups in /etc/group (not the ones in LDAP or other user database) and requires superuser privileges as it tries to open /etc/gshadow.

Despite the caveats mentioned above, this command is ideal for certain situations because it doesn’t require additional parsing of the output (i.e. cut and friends).

This could be really confusing probably because of primary/secondary difference. I think this should be avoided in favor of sudo lid -g . I have a system where this answer lists 8 users in a group whereas sudo lid -g lists 10.

groups command prints group memberships for a user. You can use lid command to list users in a group like:

Update: On Debian based distributions the command name differs as libuser-lid . Both commands are provided by libuser package as @chris-down mentioned.

$ sudo libuser-lid -g lpadmin kadir(uid=xxxx) 

What’s more, on Ubuntu 20.04 LTS, lid is part of the id-utils package. After installation it turned out that this lid does not support the -g option. I understand that Kadir answered 6 years ago, but maybe it’s time to update the information given here.

@LaryxDecidua id-utils manipulates id databases, it doesn’t work with files such as /etc/group or /etc/passwd . Its lid is not at all similar to libuser ’s.

I am surprised nobody mentioned

This command will give a list of groups the user is in.

Because — contrary to the title — the questioner wanted to know the users within a given group, not the groups of a given user, as detailed in the question. I now rephrased the title to match the contents.

Even though , is it different from the actual question, everyone will find this too as a useful information , I bet !

cut -d: -f1,4 /etc/passwd | grep $(getent group | cut -d: -f3) | cut -d: -f1 

I disagree. Because it reads users in /etc/passwd, this will not work with other nsswitch modules that access LDAP etc.

Didn’t work correctly for me: I got 4 members in a group whereas sudo lid -g lists 8. @Bhavik The accepted answer is not correct either.

Works nicely, especially if cut -d: -f1,4 /etc/passwd is replaced with getent passwd | cut -d: -f1,4 . As many people have pointed it out, getent will query non-local information sources.

Some will tell you to install libuser (for ‘lid’) or members (for ‘members’). But building upon the answer https://unix.stackexchange.com/a/349648/77959 which handled this issue with login group membership I found another group not being covered by that script. So — here’s the best of both approaches combined:

#!/bin/bash if [ $# -eq 1 ]; then gid=`getent group "$1"|cut -d: -f3` list_a=`cut -d: -f1,4 /etc/passwd | grep ":$gid$" | cut -d: -f1` list_b=`getent group "$1"|cut -d: -f4|sed 's/,/\n/g'` echo -e "$list_a\n$list_b"|grep -v "^$"|sort|uniq else echo "pass me a group to find the members of" fi 

It worked correctly on my system unlike answers involving getent or grep ‘^group_name_here:’ /etc/group

OP phrased the question to exclude the possibility of using the groups command. Since that is part of coreutils on Linux, either (a) it was removed, or (b) OP is mistyping the name.

OP could have used groups like this, for instance:

for name in $(cut -d: -f1 /etc/passwd);do groups $name|grep -w sudo|awk '';done 

One suggested answer just grep’s for the group name in /etc/group . Sometimes that works as intended.

A slightly better use of grep takes into account the syntax of /etc/group :

group_name:password:GID:user_list 

so that only the part before the first colon is a valid group-name. A plain grep without regard to syntax can (and will) pick up misleading matches from the file. Use regular expressions to make the grep match exactly what is needed:

grep -E '^users:' /etc/group |sed -e 's/^.*://' 

or using a shell variable:

grep -E '^'$groupname':' /etc/group |sed -e 's/^.*://' 

However, that only lists those not in a default group. To add those, you need to take into account the password file, e.g., by extracting the group-id number from /etc/group , and printing the users whose default group matches from /etc/passwd , e.g.,

You could do the same thing using just grep and sed, but it is more work than using awk.

Another suggested answer proposed using getent , which also is likely to be on a Linux machine (with Debian, it is part of GNU libc). However a quick check of that shows it providing only the /etc/group content.

I (like most) do not have libusers or lid installed, so I cannot comment on whether it satisfies OP’s conditions.

There is also the id program, which gives group information. Someone might expand on that as a possible answer.

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How to List All Users of a Group in Linux

Wondering which users are members of a specific group? This tutorial shows you three simple ways to list all the users of a group in Linux command line.

I have already shown you to list all the users in Linux command line. This quick tip is related and yet different from that.

I presume that you are a bit familiar with the concept of groups and users in Linux. There are several groups and a variety of users in a Linux system. A group can have multiple members while a user can be a member of several groups.

You can check which groups a particular user belongs to and you can also find all the users of a group.

List all users of a group in Linux

In this quick tutorial, I’ll show you different ways to list users in a group in Linux command line.

1. List members of a group in Linux using /etc/group file

The group information is contained in the file /etc/group. You can view the content of this file and look for the information about the members.

Normally, this file has entry in the following format:

Here’s the explanation of the fields:

• adm is the group name
• x represents password field (you won’t see password in clear text of course)
• 4 is the Group ID aka GID
• syslog and abhishek are the users belonging to the group adm

If you find manual searching for a group in the file difficult, you can use a combination of the grep command and the cut command.

grep '^group_name:.*$' /etc/group | cut -d: -f4

The above command looks for all the lines starting with the specified group name and then the cut command extract the fourth column separated with : delimiter. The result is just the name of the group members.

grep '^adm:.*$' /etc/group | cut -d: -f4 syslog,abhishek

2. List group members in Linux with getent command

getent is a multipurpose command that is used to query from database files in the /etc directory. So you can use it to query the /etc/group file and get the users of the specified group in the following manner:

This will display the line matching the group name and in here you can see the members of the group:

getent group sudo sudo:x:27:abhishek

3. List users in a group using ‘members’ command

There is a tiny command line tool that simplifies the process of listing all the members of a specific group.

The members command is usually not installed in all the systems so you have to install it on your own.

On Debian/Ubuntu based systems, you can install it using the following command:

If the command is not found in Ubuntu, you should enable the universe repository and try it again.

Once you have the command installed, you can run it like this:

For example, if you want to check which users have sudo access, you can use the members command like this:

And the output will list all the users of the sudo group.

See, it was absolutely simple to get the users belonging to a group. You learned three ways to do it.

Which method did you like the most? Or, do you use some other way to list group members in Linux? Why not share it with us here?

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How can I list all users with their username and group-name? in UNIX systems

How can I list all users with their username and group-name in UNIX systems? I want to take report form /etc/passwd file and /etc/group file In passwd file, I’ll get only GIDS but I also want to get group-name from /etc/group , and it should come in one report like I want below mention Fotomat User neme ( user ID) , Group name ,

2 Answers 2

With single awk command:

awk -F':' 'NR==FNR< a[$3]=$1; next >< print $1", "a[$4] >' /etc/group /etc/passwd 

• -F’:’ — field separator
• NR==FNR < a[$3]=$1; next >— processing the 1st input file (i.e. /etc/group ):
  • a[$3]=$1 — capture group name $1 using group identifier $3 as array a key
  • next — jump to next record
  • $1 — the 1st field; indicating user name
  • a[$4] — get group name by group id (presented by field $4 )

  its working fine with Red hat and AIX fine , but i am trying to do same in the SUNOS i am getting some different format its giving line by line , report i want to get like first Group , name but in sunos its giving one by one @RomanPerekhrest

  The following does a relational JOIN on the two files on the GID and outputs the username and group name with a : in-between:

  The GID is in column 4 in the passwd file and in column 3 in the group file.

  With -1 and -2 we specify what the join field is in the two input files and with -o we specify what fields we want to output from each file (the first field of each file).

  The sorting of each file on the join field in necessary for join to work.

  To get this in the exact format requested, just pipe it though sed ‘s/:/, /’ which replaces the colons with comma and space.

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