Rename numbered files linux

Bulk rename files with numbering

How do I bulk rename multiple files named Image401.jpg, Image402.jpg. to Image 001.jpg, Image002.jpg, . ?

2 Answers 2

Under Linux, to change the first 4 in the file names to 0 :

Under Debian, Ubuntu and derivatives, rename is a different file renaming program, which is based on a Perl expression. Either call rename.ul instead, or call the Perl renaming script:

You just want to change ‘4’ to ‘0’?

for f in Image4*.jpg do # replace Image4 prefix with Image0 newname="Image0$" mv "$f" "$newname" done 

Or you want to subtract 400 from the numeric part? Or something else?

mv «$f» Image0″$» is a much faster and safer way to do this. The $( echo | sed ) approach, even if it works on filenames like Image401.jpg , is not very robust as it will mangle filenames containing odd characters or spaces, and is much slower because of the extra temporary subshell and processes created for every single file.

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Renaming multiple files with complex numbered names

Where are you getting the number in your renamed file from? Is it at the end of the .A2010001. part of the original filename? Is there a chance that any of these number strings will have duplicate values?

If the glob MOD*.hdf is not returning any results your filenames must not be in the format you’ve stated, or you’re not in the directory containing the files.

The question Zanna asked is still not answered by OP and it is important as it will change the suggested answer. The question I have is whether the number 1 to 365 in .A2010001. A2010365 must be used in the new file name. If so, the suggested answer below will not suffice.

4 Answers 4

Since you only care about the A2010. bit, using rename in the directory with the files:

rename -n 's/.*A2010*(\d+).*/modis$1.hdf/' * 

$ rename -n 's/.*A2010*(\d+).*/modis$1.hdf/' * rename(> MOD11A1.A2010001.h24v06.006.2016025150444.hdf, modis1.hdf) rename(> MOD11A1.A2010002.h24v06.006.2016025151748.hdf, modis2.hdf) rename(> MOD11A1.A2010003.h24v06.006.2016025163706.hdf, modis3.hdf) rename(> MOD11A1.A2010365.h24v06.006.2016025150444.hdf, modis365.hdf) 

Run without -n to actually rename the files.

@Arronical \d is any digit in Perl regex, the () is a capture group, and the preceding 0* takes all the leading zeros

@Arronical \d simply is a shorthand for 1 , those shorthands are supported quite universally – for more see regular-expressions.info.

The following way uses bash parameter expansion, but it does rely on your filenames being in exactly the format you’ve stated as it relies on the placement of the numeric string to be used. This isn’t necessarily the most robust method. You must also be in the directory containing the files.

for f in MOD*.hdf; do num="$" mv "$f" modis"$((10#$num))".hdf done 

for f in MOD*.hdf; do num="$"; mv "$f" modis"$((10#$num))".hdf ; done 

This will move the files in the manner which you’ve asked for, meaning that MOD11A1.A2010001.h24v06.006.2016025150444.hdf will become modis1.hdf , MOD11A1.A2010002.h24v06.006.2016025151748.hdf becomes modis2.hdf etc.

Just noticed you removed the syntax highlighting on purpose – may I ask why? The community’s opinion on this seems to be quite clear…

You could use the rename command like this:

$ rename -n 's/MOD11A1\.A2010(. )\..*/modis$1.hdf/' MOD*.hdf rename(MOD11A1.A2010001.h24v06.006.2016025150444.hdf, modis001.hdf) rename(MOD11A1.A2010002.h24v06.006.2016025151748.hdf, modis002.hdf) rename(MOD11A1.A2010003.h24v06.006.2016025163706.hdf, modis003.hdf) 

After testing, remove -n to actually rename files.

Notes

• s/old/new replace old with new
• \. literal .
• . three characters that could be anything
• (some chars) save some chars to reference later with $1
• We could use a simple regex to match the first part of the filename in the rename command, as muru’s answer does. Sometimes you want to use a more explicit expression to distinguish between files that you do or don’t want to act on, or to be sure that your regex won’t suck up too many characters. There’s usually a lot of flexibility in solving this kind of problem.

Note that this doesn’t give you exactly what you asked for; it maintains the fixed width of the numbers. I have done this because it’s a good idea to use fixed-width numbers in filenames (otherwise they will be sorted in a confusing way, with 10 before 2, for example) (and because I haven’t figured out how to use rename to create the names you actually asked for. if I do, I will update my answer muru’s answer does that. ).

Note that Perl rename is not included in the default 17.10 installation, so if you are running 17.10 (or for future readers, perhaps a later version), start by running

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rename all files in folder to numbered list 1.jpg 2.jpg [closed]

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I have a folder full of images with several different random file names to help organize this mess I would like to, in one command rename all of them to a sequential order so if I have 100 files it starts off naming the first file file-1.jpg file-2.jpg etc. Is this possible in one command?

Try writing something yourself and then if it doesn’t work, bring it to us to help you along. You start it, we help. We don’t write it for you. Show us the actual code that you’ve tried and then we can help you from there. Chances are you’ll get pretty close to the answer if you just try it yourself first.

2 Answers 2

The most concise command line to do this I can think of is

ls | cat -n | while read n f; do mv "$f" "file-$n.jpg"; done 

ls lists the files in the current directory and cat -n adds line numbers. The while loop reads the resulting numbered list of files line by line, stores the line number in the variable n and the filename in the variable f and performs the rename.

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rename multiple files in linux with number plus a constant

where the additional constant (here 200) can be specified.

I’ve tried something along the lines of that suggested in Renaming a set of files to 001, 002, . on Linux

i=200; temp=$(mktemp -p .); for file in solution_*.vtu do mv "$file" $temp; mv $temp $(printf "solution_%0.3d.vtu" $i) i = $((i+1)) done 

but this doesn’t work for me. Thanks for any help!

Share some code you tried at this point, and explain on what you are stuck because we will not do the whole script for you

2 Answers 2

You can try with this command:

 find . -printf 'mv %f %f\n' | grep -v '\. \.' | sed 's/u Solution_/u Solution_2/g' | while read -r i ; do $i ; done 

Thank you for your reply, but this isn’t quite what I was looking for as this just appends an extra 2. I.e. if I have Solution_200.vtu Solution_201.vtu I will get Solution_2200.vtu Solution_2201.vtu instead of Solution_400.vtu, Solution_401.vtu which is what I really need.

If you have ruby on your Linux machine :

#! /usr/bin/env ruby require 'fileutils' pattern = ARGV[0] || "*.vtu" offset = (ARGV[1] || 200).to_i Dir[pattern].each do |file| if id then new_id = id.to_i + offset new_file = file.sub(/\d+/, new_id.to_s) puts "# -> #" ## UNCOMMENT THIS LINE IF YOU WANT TO MOVE FILES: # FileUtils.mv file, new_file end end 

./rename_with_integer_offset.rb "*.vtu" 200 # solution_201.vtu -> solution_401.vtu # solution_202.vtu -> solution_402.vtu 

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